Py5Shape.set_tint()
Contents
Py5Shape.set_tint()¶
Apply a color tint to a shape’s texture map.
Examples¶
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 | def setup():
py5.size(100, 100, py5.P2D)
img = py5.load_image("tower.jpg")
s = py5.create_shape()
s.begin_shape()
s.texture(img)
s.vertex(20, 20, 0, 0)
s.vertex(20, 80, 0, 100)
s.vertex(80, 80, 100, 100)
s.vertex(80, 20, 100, 0)
s.end_shape(py5.CLOSE)
s.set_tint(0, "#0000FF")
s.set_tint(2, "#FF0000")
py5.shape(s)
|
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 | def setup():
global s
py5.size(100, 100, py5.P2D)
img = py5.load_image("tower.jpg")
s = py5.create_shape()
s.begin_shape()
s.texture(img)
s.tint(0, 0, 255)
s.vertex(20, 20, 0, 0)
s.vertex(20, 80, 0, 100)
s.vertex(80, 80, 100, 100)
s.vertex(80, 20, 100, 0)
s.end_shape(py5.CLOSE)
def draw():
if py5.frame_count == 50:
s.set_tint(False)
if py5.frame_count == 100:
s.set_tint("#FF0000")
py5.shape(s)
|
Description¶
Apply a color tint to a shape’s texture map. This can be done for either the entire shape or one vertex.
This method differs from Py5Shape.tint() in that it is only to be used outside the Py5Shape.begin_shape() and Py5Shape.end_shape() methods. This method only works with the P2D and P3D renderers.
Calling this method with the boolean parameter False will delete the assigned tint. A later call with the boolean parameter True will not restore it; you must reassign the tint color, as shown in the second example.
Underlying Processing method: PShape.setTint
Syntax¶
set_tint(fill: int, /) -> None
set_tint(index: int, tint: int, /) -> None
set_tint(tint: bool, /) -> None
Parameters¶
fill: int - color value in hexadecimal notation
index: int - vertex index
tint: bool - allow tint
tint: int - color value in hexadecimal notation
Updated on March 22, 2022 21:53:01pm UTC